Silly math question about Keno?

Every Keno game I have ever seen drew 20 selections from a 80 number card.

You don’t say how many numbers are drawn by the house per game, so I’ll assume it’s still 20. This would make the odds slightly better for the player in a 75 number game than in the 80 number traditional game.

Let m = the # of spots on card
let q = the # of house draws per game
Let n = the # of selections made by the player
Let r = the # of matches in the full draw.

The probability of (n, r) =
C(n,r) • C(m-n,q-r) / C(m,q)

So for P(7,7)
m = 75
q = 20
n = 7
r = 7
C(7,7) • C(75-7,20-7) / C(75,20)
1 • 3.1369E+13 / 8.0317E+17 = 3.9056E-5

And for P(7,6)
r = 6
C(7,6) • C(75-7,20-6) / C(75,20)
7 • 1.2323E+14 / 8.0317E+17 = 1.0740E-3

So in 100 games, you have a 0.39% chance of getting 7 out of 7,
and a 10.74% of getting 6 out of 7.